Search for: In a triangle ABC, if a4+b4+c4=2a2b2+b2c2+2c2a2, then sinA= In a triangle ABC, if a4+b4+c4=2a2b2+b2c2+2c2a2, then sinA= A1B32C12D12 Register to Get Free Mock Test and Study Material +91 Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:a4+b4+c4−2a2b2+c2=b2c2⇒b2+c2−a22=3b2c2⇒b2+c2−a2=±3bc⇒2bccosA=±3bc⇒cosA=±32⇒sin2A=1−34=14⇒sinA=12Post navigationPrevious: The general solution of the equation sinx−3sin2x+sin3x=cosx−3cos2x+cos3x isNext: The domain of the function f(x)=sin-1(sin x)-cos-1(cos x) in 0,2π is Related content JEE Main 2023 Session 2 Registration to begin today JEE Main 2023 Result: Session 1 NEET 2024 JEE Advanced 2023 NEET Rank Assurance Program | NEET Crash Course 2023 JEE Main 2023 Question Papers with Solutions JEE Main 2024 Syllabus Best Books for JEE Main 2024 JEE Advanced 2024: Exam date, Syllabus, Eligibility Criteria JEE Main 2024: Exam dates, Syllabus, Eligibility Criteria