In a triangle ABC, if a4+b4+c4=2a2b2+b2c2+2c2a2, then sin⁡A= 

In a triangle ABC, if a4+b4+c4=2a2b2+b2c2+2c2a2, then sinA= 

  1. A

    1

  2. B

    32

  3. C

    12

  4. D

    12

    Register to Get Free Mock Test and Study Material

    +91

    Verify OTP Code (required)

    I agree to the terms and conditions and privacy policy.

    Solution:

    a4+b4+c42a2b2+c2=b2c2

    b2+c2a22=3b2c2b2+c2a2=±3bc2bccosA=±3bccosA=±32sin2A=134=14sinA=12

    Chat on WhatsApp Call Infinity Learn

      Register to Get Free Mock Test and Study Material

      +91

      Verify OTP Code (required)

      I agree to the terms and conditions and privacy policy.