In a △ABC , c2+a2−b2tan⁡B+a2+b2−c2tan⁡C= 

In a ABC , c2+a2b2tanB+a2+b2c2tanC= 

  1. A

    4Δ

  2. B

    8Δ

  3. C

    6

  4. D

    12

    Register to Get Free Mock Test and Study Material

    +91

    Verify OTP Code (required)

    I agree to the terms and conditions and privacy policy.

    Solution:

    we have ,

    c2+a2b2tanB+a2+b2c2tanC=2accosB×tanB+2abcosC×tanC

                                             [Using Cosine formula]

    =2acsinB+2absinC=4Δ+4Δ=8Δ

    Chat on WhatsApp Call Infinity Learn

      Register to Get Free Mock Test and Study Material

      +91

      Verify OTP Code (required)

      I agree to the terms and conditions and privacy policy.