In a ∆ABC if sides a and b remain constant such that a is the error in C, then relative error in its area, is

In a ABC if sides a and b remain constant such that a is the error in C, then relative error in its area, is

  1. A

    αcotC

  2. B

    αsinC

  3. C

    αtanC

  4. D

    αcosC

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    Solution:

    We have,

    S=12absinCdSdC=12abcosC

    Let S be the error in area S. Then,

    ΔS=dSdCΔCΔS=12abcosCα                                            [ΔC=α]

     ΔSS=12 abcosC α12  absinC= α cotC

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