MathematicsIn ΔABC , if the internal bisector of ∠A meets BC in D , then

In $Δ A B C$ , if the internal bisector of $∠ A$ meets $B C$ in $D$ , then

A
$\frac{A B}{A C} = \frac{B D}{D C}$
B
$\frac{A B}{D C} = \frac{A C}{B D}$
C
$\frac{A B}{A C} = \frac{D C}{B D}$
D
$\frac{A C}{A B} = \frac{B D}{B C}$

Solution:

By vertical angular bisector theorem

$\frac{A B}{A C} = \frac{B D}{D C}$

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