MathematicsIn ΔABC,PQ¯∥AB¯  and P,Q  are on BC  and CA  respectively. If CQ:QA=1:3  and CP=4,  then BC=

In ΔABC,PQ¯AB¯  and P,Q  are on BC  and CA  respectively. If CQ:QA=1:3  and CP=4,  then BC=

  1. A
    8
  2. B

    12

  3. C
    16
  4. D

    14

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    Solution:

    From figure

    ΔABC,PQ¯AB¯

    CPCB=CQCA (by BPT)

    4CB=14

    BC=4×4=16

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