It f(x)=x2−4x|+3| then A={x:f is not  differentiable at x} is equal to

It f(x)=x24x|+3| then A={x:f is not  differentiable at x} is equal to

  1. A

    {–1, 1, –3, 3}

  2. B

    {1, 3}

  3. C

    {1, –1}

  4. D

    {3, –3}

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    Solution:

    f(x)=|(|x|1)(|x|3)| Hence f is not differentiable at |x|=1,|x|=3 i.e. at x=1,1,3,3

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