Let A=111 and B=92−102112122132−142−152162172, then the value of A'BA is: - Sri Chaitanya Infinity Learn Best Online Courses for NCERT Solutions, CBSE, ICSE, JEE, NEET, Olympiad and Class 6 to 12

A
1224
B
1042
C
540
D
539

Solution:

$\begin{array}{l} A^{'} BA = [\begin{array}{lll} 1 & 1 & 1 \end{array}] [\begin{array}{lcc} 9^{2} & - 10^{2} & 11^{2} \\ 12^{2} & 13^{2} & - 14^{2} \\ - 15^{2} & 16^{2} & 17^{2} \end{array}] [\begin{matrix} 1 \\ 1 \\ 1 \end{matrix}] \\ = [\begin{array}{lll} 9^{2} + 12^{2} - 15^{2} & - 10^{2} + 13^{2} + 16^{2} & 11^{2} - 14^{2} + 17^{2} \end{array}] [\begin{matrix} 1 \\ 1 \\ 1 \end{matrix}] \\ = [9^{2} + 12^{2} - 15^{2} - 10^{2} + 13^{2} + 16^{2} + 11^{2} - 14^{2} + 17^{2}] \\ = [539] \end{array}$

Let $A = [\begin{array}{l} 1 \\ 1 \\ 1 \end{array}] and B = [\begin{array}{ccc} 9^{2} & - 10^{2} & 11^{2} \\ 12^{2} & 13^{2} & - 14^{2} \\ - 15^{2} & 16^{2} & 17^{2} \end{array}]$ , then the value of A'BA is:

Solution:

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