Solution:
Let
Radius of
Radius of
Now, and
Here,
Both circles are orthogonal. So, is a square.
Area of .
Let be the centers of the circles and respectively. If are the points of intersection of these circles, then the area (in sq. units) of the quadrilateral is
Let
Radius of
Radius of
Now, and
Here,
Both circles are orthogonal. So, is a square.
Area of .