Let f(x)=ax3+5×2−bx+1 .If f (x) when divided by 2x +1 leaves 5 as remainder, and f (x) is divisible by 3x -1, then

Let f(x)=ax3+5x2bx+1 .If f (x) when divided by 2x +1 leaves 5 as remainder, and f (x) is divisible by 3x -1, then

  1. A

    a=26,b=10

  2. B

     a=6 ,b=-4

  3. C

    a=26,b=12

  4. D

    a=-6,b=4

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    Solution:

    we have,

     f(12)=5 and f(13)=0a8+54+b2+1=5 and a27+59b3+1=0a+10+4b+8=40 and a9b+42=0a+4b=22 and a9b+42=0a=-6,b=4.

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