lf a + b + c=0, then the roots of the equation 4ax2+3bx+2c=0 are

lf a + b + c=0, then the roots of the equation 4ax2+3bx+2c=0 are

  1. A

    equal

  2. B

    imaginary

  3. C

    real

  4. D

    None of these

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    Solution:

     Given, a, + b + c=0 ………………..(i)
    and 4ax2+3bx+2c=0
    D=b24acD=(3b)24(4a)(2c)=9b232ac
    =9(a+c)232ac [ from Eq. (i) ]=9(ac)2+4ac>0
    Hence, roots are real. 

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