lf A,B,C and D are the angles of a cyclic quadrilateral, then cos A + cos B + cos C + cos D is equal to

# lf A,B,C and D are the angles of a cyclic quadrilateral, then cos A + cos B + cos C + cos D is equal to

1. A

2 (cos A + cos C)

2. B

2 (cos A + cos B)

3. C

2 (cos A + cos D)

4. D

0

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### Solution:

Given that, ABCD is a cyclic quadrilateral.

On adding Eqs. (i) and (ii), we get
cosA + cosB + cosC + cosD =0

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