Mathematicslog tan10+log tan 20 + ………..+ log tan890 =

$\log \tan 1^{0} + \log \tan 2^{0} + . . . . . . . . . . . + \log \tan 89^{0} =$

A
1
B
0
C
-1
D
2

Solution:

$\log \tan 1^{0} + \log \tan 2^{0} + . . . . . . . . . . . + \log \tan 89^{0} = \log (\tan 1 ° \cdot \tan 2 ° \cdot \tan 3 ° \cdot . . . \tan 45 ° . . . \tan 89 °) = \log (1) = 0$

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