sin 45300
1. A

$\frac{1}{2}$

2. B

$-\frac{1}{2}$

3. C

$\frac{\sqrt{3}}{2}$

4. D

$-\frac{\sqrt{3}}{2}$

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### Solution:

The given value is

We know that $4530=12·\left(360\right)+210$

Use the formula ${\mathbit{s}}{\mathbit{i}}{\mathbit{n}}\left(n·360°+\theta \right){\mathbf{=}}{\mathbit{s}}{\mathbit{i}}{\mathbit{n}}\left(\theta \right)$

Hence,

Use the formula ${\mathbit{s}}{\mathbit{i}}{\mathbit{n}}\left(180°+\theta \right){\mathbf{=}}{\mathbf{-}}{\mathbit{s}}{\mathbit{i}}{\mathbit{n}}\left(\theta \right)$

Therrefore,

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