tan⁡A−tan⁡B=xand cot⁡B−cot⁡A=4, then cot⁡(A−B)=

tanAtanB=xand cotBcotA=4, then cot(AB)=

  1. A

    1x+1y 

  2. B

    1x1y

  3. C

    1xy

  4. D

    x+y

    Register to Get Free Mock Test and Study Material

    +91

    Verify OTP Code (required)

    I agree to the terms and conditions and privacy policy.

    Solution:

    y=cotBcotA=1tanB1tanA=xtanAtanB

    tanAtanB=xy

    Now, 

    cot(AB)=1tan(AB)

    =1+tanAtanBtanAtanB=1+xyx=1x+1y

     

     

    Chat on WhatsApp Call Infinity Learn

      Register to Get Free Mock Test and Study Material

      +91

      Verify OTP Code (required)

      I agree to the terms and conditions and privacy policy.