MathematicsThe area of the triangle with vertices (−2,−3), (3,2), (−1,−8) is

The area of the triangle with vertices $(- 2, - 3), (3, 2), (- 1, - 8)$ is

A
$+ 12$
B
$+ 13$
C
$+ 15$
D
$+ 14$

Solution:

The area of the triangle with the vertices $(- 2, - 3), (3, 2)$ and $(- 1, - 8)$ is

$Δ = \frac{1}{2} |\begin{matrix} - 2 & - 3 & 1 \\ 3 & 2 & 1 \\ - 1 & - 8 & 1 \end{matrix}|$

$= \frac{1}{2} [- 20 + 12 - 22]$

$= + 15$ sq. units.

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