MathematicsThe area of the triangle with vertices (2,7), (1,1), (10,8) is

The area of the triangle with vertices $(2, 7), (1, 1), (10, 8)$ is

A
16 sq. units
B
$\frac{37}{2}$ sq. units
C
$\frac{47}{2}$ sq. units
D
$\frac{50}{3}$ sq. units

Solution:

The area of the triangle with the vertices $(2, 7), (1, 1), (10, 8)$ is

$Δ = \frac{1}{2} |\begin{matrix} 2 & 7 & 1 \\ 1 & 1 & 1 \\ 10 & 8 & 1 \end{matrix}| = \frac{1}{2} [- 16 + 63]$

$= \frac{47}{2}$ sq. units.

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