The base of right pyramid is a square of side 10 cm. if the height of the pyramid is 12 cm, then its

A
Slant height = 13cm
B
Lateral surface area = 260 cm²
C
Total Surface Area = 360 cm²
D
volume = 400 cm²

Solution:

Base of right pyramid is square of side (s) = 10 cm

Height of pyramid = 12 cm

$s l a n t h e i g h t = \sqrt{h^{2} + (\frac{r^{2}}{2})} = \sqrt{12^{2} + 5^{2}} = 13 c m L . S . A = \frac{1}{2} \times p e r i m e t e r o f b a s e \times s l a n t h e i g h t = \frac{1}{2} \times (4 \times 10) \times 13 = 260 c m^{2} T S A = L S A + A r e a o f b a s e = 260 + 10^{2} = 360 c m^{2} V o l u m e = \frac{1}{3} \times a r e a o f b a s e \times h e i g h t = \frac{1}{3} \times (10 \times 10) \times 12 = 400 c m^{2}$

Solution:

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