The equation of the line whose x intercept is  and which is $\frac{-5}{7}$ parallel to $3x+4y-7=0$  is

Method 1:

Equation of the line $y=m(x-a)$

Where “a” is x-intercept

$\begin{array}{l}y=\frac{-3}{4}(x+\frac{5}{7})\\ \Rightarrow 21x+28y+15=0\end{array}$

Method 2:

The equation of the line parallel to $3x+4y-7=0$  is $\Rightarrow 3x+4y+k=0\cdots \left(1\right)$

Equation (1) passes through $(\frac{-5}{7},0)$

$\begin{array}{l}\Rightarrow 3\left(\frac{-5}{7}\right)+4\left(0\right)+k=0\\ \Rightarrow k-\frac{15}{7}=0\\ \Rightarrow k=\frac{15}{7}\\ \Rightarrow 3x+4y+\frac{15}{7}=0\\ \Rightarrow 21x+28y+15=0\end{array}$