The equation of the straight line passing through the foot of the perpendicular of (4, 5) on to the X-axis and the image of the same point with respect to Y-axis is

# The equation of the straight line passing through the foot of the perpendicular of (4, 5) on to the X-axis and the image of the same point with respect to Y-axis is

1. A

$5\mathrm{x}-8\mathrm{y}-20=0$

2. B

$5\mathrm{x}+8\mathrm{y}-20=0$

3. C

$8\mathrm{x}+5\mathrm{y}+7=0$

4. D

$8\mathrm{x}-5\mathrm{y}+57=0$

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### Solution:

The foot of the perpendicular of (4, 5) on to the X-axis is (4, 0). The image of the same point (4, 5) with respect to Y-axis is (- 4, 5)

$\therefore$ The required equation is $\mathrm{y}-5=\left(\frac{-5}{8}\right)\left(\mathrm{x}+4\right)$

$⇒5\mathrm{x}+8\mathrm{y}-20=0$

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