Search for: The equation whose roots are the square of the roots of the equation 2×2+3x+1=0The equation whose roots are the square of the roots of the equation 2x2+3x+1=0A4x2+5x+1=0B4x2−x+1=0C4x2−5x−1=0D4x2−5x+1=0 Register to Get Free Mock Test and Study Material +91 Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:Let the roots of equation2x2+3x+1=0 is α and βThen ,α+β=−32 and αβ=12∴ α2+β2=(α+β)2−2αβ=−322−2×12=94−1=54and α2β2=122=14∴ Required equation isx2−α2+β2x+α2β2=0⇒ x2−54x+14=0⇒ 4x2−5x+1=0Post navigationPrevious: ∫ex1+sinx1+cosxdx is equal to Next: The distance of the point (1,-5,9) from the plane x-y+z=5 measured along a straight line x=y=z isRelated content JEE Main 2023 Result: Session 1 NEET 2024 JEE Advanced 2023 NEET Rank Assurance Program | NEET Crash Course 2023 JEE Main 2023 Question Papers with Solutions JEE Main 2024 Syllabus Best Books for JEE Main 2024 JEE Advanced 2024: Exam date, Syllabus, Eligibility Criteria JEE Main 2024: Exam dates, Syllabus, Eligibility Criteria JEE 2024: Exam Date, Syllabus, Eligibility Criteria