Search for: The general solution of the equation sec4θ−sec2θ=2 is θ=The general solution of the equation sec4θ−sec2θ=2 is θ=A(2n+1)π2B(2n+1)π5C(2n+1)π3D(2n-1)π10 Register to Get Free Mock Test and Study Material +91 Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:1cos4θ−1cos2θ=2⇒ cos2θ−cos4θ=2cos4θcos2θ=cos6θ+cos2θ∴ cos6θ+cos4θ=0⇒ 2cos5θcosθ=0cosθ=0⇒θ=(2n+1)π2,cos5θ=0⇒θ=(2n+1)π10Post navigationPrevious: Circles with radii 3, 4, 5 touch each other externally. If S is the point of intersection of tangents to these circles at their points of contact, then the distance of S from a point of contact is Next: For, x∈R,x≠0,x≠1, let f0(x)=11−xand fn+1(x)=f0fn(x),n=0,1,2,….Then the value of f100(3)+f123+f232 is equal to :Related content JEE Main 2023 Question Papers with Solutions JEE Main 2024 Syllabus Best Books for JEE Main 2024 JEE Advanced 2024: Exam date, Syllabus, Eligibility Criteria JEE Main 2024: Exam dates, Syllabus, Eligibility Criteria JEE 2024: Exam Date, Syllabus, Eligibility Criteria NCERT Solutions For Class 6 Maths Data Handling Exercise 9.3 JEE Crash Course – JEE Crash Course 2023 NEET Crash Course – NEET Crash Course 2023 JEE Advanced Crash Course – JEE Advanced Crash Course 2023