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The height of a cone is 3m and the diameter of its base is 8m. Then its

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a

Slant height = 5m

b

Curved surface area = 65 m²

c

Total surface area = 113 cm²

d

volume = 50 m²

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detailed solution

Correct option is A

$H e i g h t o f c o n e (h) = 3 m B a s e d i a m e t e r (d) = 8 m R a d i u s o f b a s e (r) = 4 m S l a n t h e i g h t = \sqrt{(h^{2} + π^{2})} = \sqrt{(3^{2} + 4^{2})} = 5 m . C S A o f c o n e = π r l = \frac{22}{7} \times 4 \times 5 = 62.85 m^{2} T S A o f c o n e = π r (l + r) = \frac{22}{7} \times 4 (5 + 4) = 113.1 m^{2} V o l u m e o f c o n e = \frac{1}{3} π r^{2} h = \frac{1}{3} \times \frac{22}{7} \times 4 \times 4 \times 3 = 50.28 m^{2}$

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