The height of a cone is 3m and the diameter of its base is 8m. Then its “Volume”

The height of a cone is 3m and the diameter of its base is 8m. Then its “Volume”

A
$72.28 m^{3}$
B
$60.33 m^{3}$
C
$90.28 m^{3}$
D
$50.28 m^{3}$

Solution:

$h = 3 m$

$d = 8 m$

$r = \frac{d}{2} = \frac{8}{2} = 4 m$

$Volume = \frac{1}{3} π r^{2} h$

$= \frac{1}{3} \times \frac{22}{7} \times 4 \times 4 \times 3$

$= \frac{352}{7}$

$= 50.28 m^{3}$

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