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The most general solution of tanθ=1,cosθ=12 is

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a
nπ+7π4,nZ
b
πz+(1)n7π4,nZ
c
2nπ+7π4,nZ
d
none of these

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detailed solution

Correct option is C

We have

tanθ=1 and cosθ=12

The value of θ lying between 0 and 2π and satisfying these

is 7π4 Therefore, the most general solution is

θ=2nπ+7π4, where nZ

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