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The most general values of θ satisfying   2cosθ+3=0 and 3tanθ1=0 are given by

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a
nπ±π6,nZ
b
2nπ±π6,nZ
c
2nπ+7π6,nZ
d
none of these

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detailed solution

Correct option is C

We have ,

cosθ=32 and tanθ=13

A value of θ in [θ, 2π] satisfying these two equations is 7π6.

Hence, the general value of θ is given by θ=2nπ+7π6,nZ 

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