The number of four digited numbers formed by 1, 2, 5, 6, 7 divisible by 25 is

Given digits are 1, 2, 5, 6, 7

A number is divisible by 25 when last 2 digits of the number is divisible by 25.

Last 2 boxes can be filled by 25, 75 in 2 ways

Remaining 2 boxes can be filled by remaining 3 digits in $^{3} P_{2}$ ways.

$∴$ Required 4 digit numbers $=^{3} P_{2} \times 2$

$= 12$

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