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Q.

The number of ways in which 10 candidates A1,A2,,A10 can be ranked so that A1 is always above A2,  is

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a

10!2

b

9!

c

10!

d

none of these

answer is B.

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Detailed Solution

Ten candidates can be ranked in 10 ! ways. In half of these ways A1 is above A2 and in another half A2 is above A1. So, required number of ways =10!2

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