The number of words that can be made by arranging the letter of the word “ROORKEE” that neither begin with R nor end with E is

The number of words that can be made by arranging the letter of the word “ROORKEE” that neither begin with R nor end with E is

Solution:

No. of ways $= \frac{7!}{(2!)^{3}} - \frac{6!}{(2!)^{2}} - \frac{6!}{(2!)^{2}} + \frac{5!}{2!} = 330$

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