MathematicsThe point P (a,b) lies on the straight line 3x-2y=13 and the point Q (b, a) lies on the staright line 4x-y=5 then the equation of line PQ is

The point P (a,b) lies on the straight line 3x-2y=13 and the point Q (b, a) lies on the staright line 4x-y=5 then the equation of line PQ is

  1. A

    x + y = 7

  2. B

     x + y = 9

  3. C

     x + y = 2

  4. D

     x + y = 21

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    Solution:

    Pa,b lies on 3x  2y  13 = 03a2b13=01Qb,alieson4xy5=04ba5=0a4b+5=02Solving1&2ab1213324514a1052=b1315=112+2a62=b28=110  a=6210=315,    b=2810=145  P315,  145  and  Q145,  315

    Slope  of  PQ=315145145315=1717=1Equation  of  PQ¯   y=145=1x315  5y14=5x+315x+5y45=0x+y=9

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