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The points of contact of the tangents drawn from the origin to the curve y=x2+3x+4 are

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a
(2, 14), (–2, 12)
b
(2, 12), (–2, 2)
c
(2, 14), (–2, 2)
d
(2, 12), (–2, 14)

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detailed solution

Correct option is C

Point on the Curve Px1 y1 is y1=x12+3x1+4     -(1)

dydx=2x+3    dydxPx1 y1 =2x1+3

eq of Tangent y-y1=2x1+3 x-x1

Passes through 0, 0    -y1=2x1+3 -x1

eq (1) sub  x12+3x1+4=x12x1+3

                                  x12=4              x1=±2x1=2   y1=4+6+4=14x1=-2  y1=4-6+4=2

 Points (2, 14) (-2, 3)

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