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The probabilities that a student passes in mathematics, physics and chemistry are m, p and c respectively of these subjects the students has 75%  chance of passing in at least one, a 50% chance of passing in at least two, and a 40% chance of passing in exactly two. Which of the following
relations are true?

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a
p+m+c=1920
b
p+m+c=2720
c
pmc=110
d
pmc=14

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detailed solution

Correct option is B

We have P(ABC)=34
 I.e, P(A)+P(B)+P(C)P(AB)P(BC)P(CA)+P(ABC)(i)
P(AB)+P(BC)+P(AC)
 2P(ABC)=12( ii )
And P(AB)+P(BC)+P(AC)
3P(ABC)=25( iii )
From eq’s (ii) and (iii) we get
P(ABC)=1225=110(iv)P(A)P(B)P(C)=110PMC=110
From eq’s (i) ,(ii) and (iii) we have
P(A)+P(B)+P(C)12+210+110=34P+m+c=2720

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