Search for: The value of ∫esecx⋅sec3xsin2x+cosx+sinx+sinxcosxdx isThe value of ∫esecx⋅sec3xsin2x+cosx+sinx+sinxcosxdx isAesecxsec2x+secxtanx+CBesecx+CCesecx(secx+tanx)+CDnone of these Register to Get Free Mock Test and Study Material +91 Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:We have, 1=∫esecxtan2xsecx+sec2x +tanxsec2x+tanxsecxdx⇒ I=∫esecx[secxtanx(secx+tanx) +secxtanx+sec2xdx⇒ I=∫esecxsecxtanxII⋅(secx+tanxI)dx +∫esecx⋅secxtanx+sec2xdx⇒ I=(secx+tanx)esecx−∫secxtanx+sec2xesecxdx +∫esecxsecxtanx+sec2xdx⇒ I=esecx(secx+tanx)+CPost navigationPrevious: lf the value of the integral ∫01/2 x21−x23/2dx is k6, then k is equal toNext: The integral ∫π/6π/3 tan3xsin23x2sec2xsin23x+3tanxsin6xdx is equal to Related content NEET Rank Assurance Program | NEET Crash Course 2023 JEE Main 2023 Question Papers with Solutions JEE Main 2024 Syllabus Best Books for JEE Main 2024 JEE Advanced 2024: Exam date, Syllabus, Eligibility Criteria JEE Main 2024: Exam dates, Syllabus, Eligibility Criteria JEE 2024: Exam Date, Syllabus, Eligibility Criteria NCERT Solutions For Class 6 Maths Data Handling Exercise 9.3 JEE Crash Course – JEE Crash Course 2023 NEET Crash Course – NEET Crash Course 2023