The value of 2∫sin⁡xdxsin⁡x−π4 is equal to

The value of 2sinxdxsinxπ4 is equal to

  1. A

    xlogcosxπ4+C

  2. B

    x+logcosxπ4+C

  3. C

    xlogsinxπ4+C

  4. D

    x+logsinxπ4+C

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    Solution:

    Let I=2sinxsinxπ4dx

    Put, x=π4=tdx=dt

    I=2sinπ4+tdtsint=212cott+12dt=log|sint|+t+C=x+logsinxπ4+C

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