Search for: The value of 6sin6θ+cos6θ−9sin4θ+cos4θ+4 isThe value of 6sin6θ+cos6θ−9sin4θ+cos4θ+4 isA-3B1C0D3 Register to Get Free Mock Test and Study Material +91 Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:6sin6θ+cos6θ−9sin4θ+cos4θ+4=6sin2θ+cos2θ3−3sin2θcos2θsin2θ+cos2θ−9sin2θ+cos2θ2−2sin2θcos2θ+4=61−3sin2θcos2θ−91−2sin2θcos2θ+4=6−9+4=1Post navigationPrevious: If 2sinα1+cosα+sinα=x,then 1−cosα−sinαcosα is equal toNext: If tanA+sinA=m and tanA−sinA=n then m2−n22mn is equal toRelated content JEE Main 2023 Result: Session 1 NEET 2024 JEE Advanced 2023 NEET Rank Assurance Program | NEET Crash Course 2023 JEE Main 2023 Question Papers with Solutions JEE Main 2024 Syllabus Best Books for JEE Main 2024 JEE Advanced 2024: Exam date, Syllabus, Eligibility Criteria JEE Main 2024: Exam dates, Syllabus, Eligibility Criteria JEE 2024: Exam Date, Syllabus, Eligibility Criteria