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Q.

The value of 6sin6θ+cos6θ9sin4θ+cos4θ+4 is

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a

1

b

-3

c

0

d

3

answer is B.

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Detailed Solution

6sin6θ+cos6θ9sin4θ+cos4θ+4=6sin2θ+cos2θ33sin2θcos2θsin2θ+cos2θ9sin2θ+cos2θ22sin2θcos2θ+4=613sin2θcos2θ912sin2θcos2θ+4=69+4=1

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