The value of f∫1+xxdx, is

The value of f1+xxdx, is

  1. A

    21+x+log1+x11+x+1+C

  2. B

    21+x+C

  3. C

    loge1+x11+x+1+C

  4. D

    1+x11+x+1+C

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    Solution:

    Let 

    I=1+xxdx

     I=t2t212tdt, where 1+x=t2

     t=2t21+1t21dt=21+1t21dt I=2t+logt1t+1+C=21+x+log1+x11+x+1+C

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