Search for: The value of sin(B+A)+cos(B−A)sin(B−A)+cos(B+A) is equal toThe value of sin(B+A)+cos(B−A)sin(B−A)+cos(B+A) is equal toAcosB+sinBcosB−sinBBcosA+sinAcosA−sinACcosA−sinAcosA+sinADNone of these Register to Get Free Mock Test and Study Material +91 Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:=sin(B+A)+cos(B−A)sin(B−A)+cos(B+A)=sin(B+A)+sin90∘−B−Asin(B−A)+sin90∘−B+A=2sinA+45∘cos45∘−B2sin45∘−Acos45∘−B=sinA+45∘sin45∘−A=12sinA+12cosA12cosA-12sinA=cosA+sinAcosA−sinAPost navigationPrevious: The expression cos2(A−B)+cos2B−2cos(A−B)cosAcosB isNext: The mean and variance of n values of a variable x are 0 and σ2, respectively. If the variable y = x2 then mean of y is Related content JEE Main 2023 Question Papers with Solutions JEE Main 2024 Syllabus Best Books for JEE Main 2024 JEE Advanced 2024: Exam date, Syllabus, Eligibility Criteria JEE Main 2024: Exam dates, Syllabus, Eligibility Criteria JEE 2024: Exam Date, Syllabus, Eligibility Criteria NCERT Solutions For Class 6 Maths Data Handling Exercise 9.3 JEE Crash Course – JEE Crash Course 2023 NEET Crash Course – NEET Crash Course 2023 JEE Advanced Crash Course – JEE Advanced Crash Course 2023