The values of 4 sin2 θ- cos 2 θ lies in the interval

The values of 4 sin2 θ- cos 2 θ lies in the interval

  1. A

    -1, 5

  2. B

    -1, 5

  3. C

    (-, -1)  5, 

  4. D

    none of these

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    Solution:

    Let x=4sin2θcos2θ. Then,

              x=2(1cos2θ)cos2θ x=23cos2θ

    Now,

         33cos2θ3                                [1cos2θ1]

     2323cos2θ2+3 1x5x[1,5].

     

     

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