Mathematics The surface area of a cube of dimensions n×n×n is painted and it cut into n cubes of equal length (1 unit), then number of 2 faces painted cubes are

$The surface area of a cube of dimensions n \times n \times n is painted and it cut into n cubes of equal length (1 unit), then number of 2 faces painted cubes are$

A
$8 n − 2$
B
$6 n − 2$
C
$12 n − 2$
D
$4 n − 2$

Solution:

Surface area of cube of dimension

$n × n × n$

are painted

Number of 2 faces painted cubes

$= 12 n − 2$

Solution:

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