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Two different families A and B are blessed with equal number of children. There of 3 tickets to be disributed amongst the chidren of these famimies so that no child gets more than one ticket. 

If the probability that all the tickets go to the children of the family B is 112, , then the number of children in each family

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a
4
b
6
c
3
d
5

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detailed solution

Correct option is D

Let each family has 'n' children 3 tickets distributed among children 

n(S)-2nC3

E=all tickets goes to children B

n(E)=nC3    P(E)=nC32nC3=n(n-1) (n-2)2n(2n-1) (2n-2)n-24(2n-1)=112    3n-6=2n-1                                n=5

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