Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6

Q.

Which of the following pairs of linear equations has unique solution, no solution, or infinitely many solutions. In case there is a unique solution, find it by using cross multiplication method. 

(i) x – 3y – 3 = 0 and 3x – 9y – 2 = 0

(ii) 2x + y = 5  and 3x + 2y = 8

(iii) 3x – 5y = 20 and 6x – 10y = 40

(iv) x – 3y – 7 = 0 and 3x – 3y – 15 = 0

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

answer is 1.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

(i) x – 3y – 3 = 0 and 3x – 9y – 2 = 0

a1a2=13, b1b2=-3-9=13,c1c2=-3-2=32 

a1a2=b1b2c1c2

Since, the given set of lines are parallel to each other, they will not intersect each other. Hence, there is no solution for these equations.

Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
Which of the following pairs of linear equations has unique solution, no solution, or infinitely many solutions. In case there is a unique solution, find it by using cross multiplication method. (i) x – 3y – 3 = 0 and 3x – 9y – 2 = 0(ii) 2x + y = 5  and 3x + 2y = 8(iii) 3x – 5y = 20 and 6x – 10y = 40(iv) x – 3y – 7 = 0 and 3x – 3y – 15 = 0