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1 ampere current is equivalent to

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6 .25 \times 10^{18}

electrons s^-1

2 .25 \times 10^{18}

electrons s^-1

6 .25 \times 10^{14}

electrons s^-1

2 .25 \times 10^{14}

electrons s^-1

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detailed solution

Correct option is A

$q = i . t = n . e \Rightarrow \frac{n}{t} = \frac{i}{e} \Rightarrow \frac{n}{t} = \frac{1}{1 .6 \times 10^{- 19}} = 6 .25 \times 10^{18} electronics s^{- 1}$

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