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Q.

A homogeneous solid cylinder of length L(L<H/2) and cross-sectional area A/5 is immersed such that it floats with its axis vertical at the liquid-liquid interface with length L/4 in the denser liquid as shown in the figure where d denotes density. The lower density liquid is open to atmosphere having pressureP0 . The density D of solid is given by                       

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a

45d

b

d

c

d5

d

54d

answer is A.

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Detailed Solution

Law of floatation

Weight of cylinder = up thrust due to both liquids

Mg=(A5×L4)(2d)g+(A5.3L4)dg

D.A5×Lg=A5L42dg+A5.3L4dg

D=d2+3d4=5d4

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