A body is projected, making an acute angle with the horizontal. If angle between velocity v→ and accelerationg→ is θ  then θis given by

A body is projected, making an acute angle with the horizontal. If angle between velocity $\stackrel{\to }{\mathrm{v}}$ and acceleration$\stackrel{\to }{\mathrm{g}}\text{\hspace{0.17em}}\mathrm{is}\text{\hspace{0.17em}}\mathrm{\theta }$  then $\mathrm{\theta }$is given by

1. A

$\mathrm{\theta }={90}^{0}$

2. B

$\mathrm{\theta }={0}^{0}$

3. C

${90}^{0}<\theta <{0}^{0}$

4. D

${0}^{0}<\mathrm{\theta }<{180}^{0}$

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Here velocity is acting upwards when projectile is going upwards and acceleration is downwards. The angle $\mathrm{\theta }$  between $\stackrel{\to }{\mathrm{v}} \mathrm{and} \stackrel{\to }{\mathrm{a}}$ is more than 0° and less than  180°