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A capacitor is connected to a 12 V battery through a resistance of 10Ω . It is found that the potential difference across the capacitor rises to 4.0 V in 1µS . Find the capacitance of the capacitor. 

(Given  ln32=0.405)

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a
0.25 μF
b
1μF
c
2μF
d
0.6μF

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detailed solution

Correct option is A

The charge on the capacitor during charging is given by Q=Q01et/RC .
Hence, the potential difference across the capacitor is
V=Q/C=Q0/C1et/RC
Here at t = 1µs , the potential difference is 4 V whereas the steady state potential difference is Q0/C=12V.S0,4V=12V1et/RC .Or,   1et/RC=13    Or,  et/RC=23
Or,    tRC=ln32=0.405 Or,  RC=t0.405=1μs0.405=2.469μs
Or,   C=2.46910Ω0.25μF
 

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