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A mass M attached to a spring oscillates with a period of 2 sec. If the mass is increased by 2kg, the period increases by 1 sec the initial mass M is

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1.6 kg

3.2 kg

4.8 kg

0.8 kg

answer is A.

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Detailed Solution

$T = 2 π \sqrt{\frac{M}{K}};$

$\Rightarrow 2 = 2 π \sqrt{\frac{M}{K}}; 3 = 2 π \sqrt{\frac{M + 2}{K}}$

$\Rightarrow \frac{9}{4} = \frac{M + 2}{M}$

$\Rightarrow 9 M = 4 M + 8 \Rightarrow 5 M = 8;$

$\Rightarrow M = \frac{8}{5} = 1 .6 kg$

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