Q.

A non – conducting ring of radius R having uniformly distributed charge Q starts rotating about X X'  axis passing through the  centre in the plane of the ring with an angular acceleration 'α' as shown in the figure.  Another small conducting ring having radius a(a<<R) is kept fixed at the centre of bigger ring in such a way that the axis  is passing through its centre and perpendicular to its plane.  If the resistance of the small ring is r=1Ω, find the induced current in it (in ampere).
Question Image
(Given  Q=16×102μoC,R=1m,a=0.1m,α=8rad/s2)

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answer is 16.

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Detailed Solution

dq=qdθ2π, di=dqT=qωdθ2π2π=qω4π2dθ

Magnetic Field on axis at center is given by,

dB=μOdi(r)22r2+x23/2

here r=Rsinθ and r2+x2=R
dB=μOdi(Rsinθ)22R3 dB=o2πμOsin2θ2Rqω4π2dθ


Question Image
B=μoqω8πR  =Bπa2=πa2μoqω8πR=μoqωa28R
 induced emf; ∈=ddt=μoqa28Rα=16V i=161=16A

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