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A particle starts SHM from the mean position. Its amplitude is A and its time period is T. At one time its speed is half that of the maximum speed. Its displacement is

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\frac{\sqrt{2} A}{3}

\frac{\sqrt{3} A}{2}

\frac{2 A}{3}

\frac{3 A}{\sqrt{2}}

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detailed solution

Correct option is B

$V = ω \sqrt{A^{2} - x^{2}} \Rightarrow \frac{A ω}{2}$

$= ω \sqrt{A^{2} - x^{2}} = \frac{\sqrt{3}}{2} A .$

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