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A potentiometer wire has a length of 4m and resistance $20 Ω$ . It is connected in series with a resistance of $2980 Ω$ and a cell of emf 4V and negligible internal resistance. The potential gradient of the wire is _________ $\times 10^{- 2} {Vm}^{- 1}$

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detailed solution

Correct option is @

$I = \frac{E}{R + R_{1}} = \frac{4}{20 + 2980} = \frac{4}{3000} A$

$V = IR = \frac{4}{3000} \times 20 = \frac{8}{300} V$

$∴ The potentail gradient = \frac{V}{L} = \frac{8}{300 \times 4} = 0 .67 \times 10^{- 2} {Vm}^{- 1}$

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detailed solution

Correct answer is 0.67

$I = \frac{E}{R + R_{1}} = \frac{4}{20 + 2980} = \frac{4}{3000} A$

$V = IR = \frac{4}{3000} \times 20 = \frac{8}{300} V$

$∴ The potentail gradient = \frac{V}{L} = \frac{8}{300 \times 4} = 0 .67 \times 10^{- 2} {Vm}^{- 1}$

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A potentiometer wire has a length of 4m and resistance 20Ω. It is connected in series with a resistance of 2980Ω and a cell of emf 4V and negligible internal resistance. The potential gradient of the wire is _________ ×10−2Vm−1