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A small piece of metal wire is dragged across the gap between the pole pieces of a magnet in 0.4 sec. If magnetic flux between the pole pieces is known to be 8 × 104Wb, then induced emf in the wire, is

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a
4 × 10–3 V
b
8 × 10–3V
c
2 × 10–3V
d
6 × 10–3V

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detailed solution

Correct option is C

Emf(e)=dϕdt=8×1040.4=2×103V

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