A thermodynamic system undergoes cyclic process ABCDA as shown in figure. The work done by the system in the cycle is

A thermodynamic system undergoes cyclic process ABCDA as shown in figure. The work done by the system in the cycle is

A
$P_{0} V_{0}$
B
$2 P_{0} V_{0}$
C
$\frac{P_{0} V_{0}}{2}$
D
Zero

Solution:

$W = Area of BCE + Area of ADE$

= $- W_{0} + W_{0} = 0$

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