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An electric bulb is rated $220 V - 100 W$ . The power consumed by it when operated on 110 V will be

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detailed solution

Correct option is C

$R = \frac{V_{R}^{2}}{P_{R}}$

We are using same bulb so R is constant.

$∴ P_{R} \propto V^{2}$

Thus, when voltage drop becomes half , power output becomes one fourth.

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An electric bulb is rated 220 V−100 W. The power consumed by it when operated on 110 V will be